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[jjipper] WEEK 01 solutions #2395
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,16 @@ | ||
| /** | ||
| * https://leetcode.com/problems/contains-duplicate | ||
| * time complexity : O(n) | ||
| * space complexity : O(n) | ||
| */ | ||
|
|
||
| export function containsDuplicate(nums: number[]): boolean { | ||
| const seen = new Set<number>(); | ||
| for (const num of nums) { | ||
| if (seen.has(num)) { | ||
| return true; | ||
| } | ||
| seen.add(num); | ||
| } | ||
| return false; | ||
| }; | ||
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,18 @@ | ||
| /** | ||
| * https://leetcode.com/problems/two-sum | ||
| * time complexity : O(n) | ||
| * space complexity : O(n) | ||
| */ | ||
|
|
||
| export function twoSum(nums: number[], target: number): number[] { | ||
| const obj: Record<number, number> = {}; | ||
| for (let i = 0; i < nums.length; i++) { | ||
| const a = nums[i]; | ||
| const b = target - a; | ||
| if (b in obj) { | ||
|
Contributor
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 깔끔한 풀이네요.
Contributor
Author
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 앗 그러네요 변수명도 의미있게 작성하도록 신경써야겠습니다. |
||
| return [obj[b], i]; | ||
| } | ||
| obj[a] = i; | ||
| } | ||
| return []; | ||
| }; | ||
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이 방식이라면 Set에 모든 숫자를 넣지 않는 경우도 생겨서
모두 넣고 사이즈를 비교하는 방식보다 효율적일 것 같습니다.
의미도 명확해서 좋은 풀이인 것 같네요!