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20 changes: 20 additions & 0 deletions combination-sum/sangbeenmoon.py
Original file line number Diff line number Diff line change
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# TC : O(2^target) 재귀 트리의 분기 수
# SC : O(target/min(candidates)) 재귀 스택 깊이

class Solution:
def combinationSum(self, candidates: List[int], target: int) -> List[List[int]]:
self.answer = []
for i in range(len(candidates)):
self.go(i, candidates, [candidates[i]], candidates[i], target)

return self.answer

def go(self, i:int, candidates: List[int], nums: List[int], sum_: int, target: int):
if sum_ == target:
self.answer.append(nums.copy())

for j in range(i, len(candidates)):
if candidates[j] + sum_ <= target:
nums.append(candidates[j])
self.go(j, candidates, nums, sum_ + candidates[j], target)
nums.pop()
36 changes: 36 additions & 0 deletions decode-ways/sangbeenmoon.py
Original file line number Diff line number Diff line change
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# idea
# 마지막 두자리 수가 독립 가능 -> dp[i] = dp[i-1] + dp[i-2]
# 마지막 한자리 수가 독립 가능 -> dp[i] = dp[i-1]
# 위 두 케이스 모두 불가능 -> 0 반환
# TC : O(n)
# SC : O(n)

class Solution:
def numDecodings(self, s: str) -> int:
dp = [1] * len(s)

if s[0] == '0':
return 0

if '1' <= s[0] and s[0] <= '9':
dp[0] = 1

for i in range(1, len(s)):
target = s[i-1:i+1]

if int(s[i]) != 0 and 10 <= int(target) and int(target) <= 26:
dp[i] = dp[i-1] + dp[i-2]
continue

if int(s[i]) == 0 and 10 <= int(target) and int(target) <= 26:
dp[i] = dp[i-2]
continue

target = s[i]
if 1 <= int(target) and int(target) <= 9:
dp[i] = dp[i-1]
continue

return 0

return dp[len(s) - 1]
12 changes: 12 additions & 0 deletions maximum-subarray/sangbeenmoon.py
Original file line number Diff line number Diff line change
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# 30분 내로 풀지 못함.
# prefix sum 을 사용해서 풀어보려고 했으나 시간 초과.
# dp 문제임을 파악할 수 있는 직관 필요...

class Solution:
def maxSubArray(self, nums: List[int]) -> int:
dp = [0] * len(nums)
dp[0] = nums[0]
for i in range(1, len(nums)):
dp[i] = max(nums[i], nums[i] + dp[i-1])

return max(dp)
9 changes: 9 additions & 0 deletions number-of-1-bits/sangbeenmoon.py
Original file line number Diff line number Diff line change
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class Solution:
def hammingWeight(self, n: int) -> int:
cnt = 0
while n > 0:
if n % 2 == 1:
cnt = cnt + 1
n = n // 2
print(n)
return cnt
21 changes: 21 additions & 0 deletions valid-palindrome/sangbeenmoon.py
Original file line number Diff line number Diff line change
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# TC : O(n)
# SC : O(n)

class Solution:
def isPalindrome(self, s: str) -> bool:
refined_s = []

for ch in s:
if 'a' <= ch and ch <= 'z' or ('0' <= ch and ch <= '9'):
refined_s.append(ch)
continue

if 'A' <= ch and ch <= 'Z':
refined_s.append(ch.lower())

for i in range(len(refined_s)):
j = len(refined_s) - i - 1
if refined_s[i] != refined_s[j]:
return False

return True
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